setCharAt() StringBuffer Example

December 8, 2014 | class StringBuffer
To manipulate string, java.lang.StringBuffer class comes with many methods, otherwise, which will take long laborious coding as in C/C++. One such method is setCharAt(int, char) that replaces a single character in the string buffer. Now read setCharAt() StringBuffer.

What Java API says of setCharAt() StringBuffer:

  • public synchronized void setCharAt(int index1, char1): Replaces the character in the StringBuffer at index number index1 with character char1.
Following setCharAt() StringBuffer example illustrates.
public class Demo
{
  public static void main(String args[])
  {						
   StringBuffer sb1 = new StringBuffer("ABCDEFGHI");
   
   System.out.println("Original string buffer sb1: " + sb1);

   sb1.setCharAt(0, 'a');
   sb1.setCharAt(4, 'e');

   System.out.println("String buffer sb1 after setting char: " + sb1);  

   sb1.setCharAt(10, 'y');
 }
}

setCharAt() StringBuffer Output screenshot on setCharAt() StringBuffer Example

sb1.setCharAt(0, 'a'); sb1.setCharAt(4, 'e'); sb1.setCharAt(10, 'y');

setCharAt(0, 'a') replaces A (at 0 index number) with a and setCharAt(4, 'e') replaces E (at 4 index number) with e. We have seen earlier how to replace a group of characters.

setCharAt(10, 'y') throws StringIndexOutOfBoundsException as 10th index number does not exist in sb1.

A similar example exists replacing a group of characters "replace() StringBuffer Example".